032258Currently, my code just returns zero on the right side of the decimal place. date_to) - (DATEDIFF(WK, evnt. select trunc (months_between (:end_date,. then the following should be the result. ROUND (TO_NUMBER (END_DATE - START_DATE) * 24) 分钟：. If date1 is earlier than date2 , then the result is negative. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Oracle's database does not have (nor need) a datediff() function. If year numbers are different calculation of 52 * year difference + week number. lastModified and w. SELECT TIMESTAMPDIFF (MONTH, '2012-05-05', '2012-06-04') -- Outputs. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. I would like to create a stored procedure that will create a row in a table for every day in a given date range. datediff('MONTH', pr. DiffYears Returns the difference in years between two dates. Oracle SQL Hours Difference between dates in HH:MM:SS. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. Truncate a Date to a Specific Unit of Measure. SYSDATE) and subtracting a date from a timestamp (e. Calculate difference between 2 date / times in Oracle SQL. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. see this sqlfiddle. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN() will return fractions of months, so use TRUNC() or ROUND() if you need an integer number. Examples of Results in Months. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. TIMESTAMP Functions. For example, between those dates: "03/03/2020 - 06/06/2020" I need something like "(03,04,05,06)". , YEAR, MONTH, DAY,. The unit of time. AgeInYears value of 0 while in the other case the AgeInYears value is 1. for oracle: months_between. To get the months or years separately, use extract. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). Select(x => x. In the ORDER BY clause, you want to order by the actual date. ELSE 'DATE column' between 'first of current month' and 'current. 2 Answers Sorted by: 0 The best thing to do in this case is to use Oracle's MONTHS_BETWEEN () function. SELECT TO_DATE (“2021-01-15”) as “Date value”; TO_CHAR. We’re calculating months of service in this example. Sorted by: 193. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). The datediff function can return the difference between two dates in days, months, years, minutes, etc. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. Also I am not sure about Oracle, mysql,. Extract a value of a date time field e. e. For instance, select datediff (day,'1 Jan 2000' ,'18 April 2014') / 365. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. g for me the max dates is 1399, You can calculate this with select count(*) from sys. The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. I am trying to use the INTNX function to get the first and last days of the previous month. NET SQL Added in; EF. Oracle GoldenGate add trandata errors. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. We would like to show you a description here but the site won’t allow us. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters):. 005479 0. columns c puts a limit on how many dates are returned. Subtracts a specified time interval from a DATE value. Move the start date to the next Monday, then add the calculated weeks. I used the following code: SELECT h. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. 7 Date and Time Functions. date_from, evnt. 1. Share. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. StartDate) AND. CREATE FUNCTION trunc_date (@date DATETIME) RETURNS DATETIME AS BEGIN SELECT CONVERT (varchar, @date,112) END. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. 0. The dateadd function adds or subtracts a number of specified time units from a given date. It would need to be EndDate + 23:59:59. SQL is a standard language for storing, manipulating and retrieving data in databases. For many values of the local settings, this would simply fail. Oracle常用函数:DateDiff () 返回两个日期之间的时间间隔自定义函数. Modified 3 months ago. To retrieve this number, use any of the following functions: Today (), TodateEx (), GetFirstDate (), GetLastDate (), DateRoll (). A) Get the difference in months of dates on the same day. 1. Share. If the days of the month are both the last day of the month (e. Oracle equivalent to SQL Server/Sybase DateDiff. 2425. Add a. Assuming that a. MySQLには MONTH 機能がありますが、Oracleにはありません。 存在しない関数 DATEDIFF が無効なIDであるのと 同じ理由。 ORA-00904の解決策は、 EXTRACTという名前の正しいOracle関数 を呼び出して、列の月の値を取得することです。Use DATEADD and DATEDIFF() function together in SQL query. For formatting functions, refer to Section 9. Viewed 32k times. I am trying to create a new column that will show the age of the person on the date that they took up the membership. maybe something like passing an "m" as one of the parameters. This formula subtracts the first day of the ending month (5/1/2016) from the original end date in cell E17 (5/6/2016). Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. Asked 10 years, 2 months ago. txt","contentType":"file"},{"name. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Functions. PostgreSQL - Date Difference in Months. join our newsletter and get access to exclusive content every month. Adds the specified number of months to a date or timestamp. , SYSDATE - pr. I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. The month is created in the table from the delivery date in the format 01/mm/yyyy. VALID_FROM_DTTM between DATEADD(m,-1,DATEADD(m, DATEDIFF(m,0,GETDATE()),0)) and. Must be a date, a time, a timestamp, or an expression that can be evaluated to a date, a time, or a timestamp. Arguments. 利用日期间的加减运算. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. For example, only one set of /*+ */ is allowed. One option that avoids needing to add EndDate + 23:59:59. sample: SELECT months_between(column1,column2) FROM Table Share. Syntax¶ MONTHS. Syntax DATEDIFF (datepart ,startdate ,enddate) datepart Abbreviations year. Not all of the expressions described at the URL are supported in NetSuite. You could, of course, write your own function and call that. lastModified and w. 1. The Oracle ROUND () function takes two arguments: 1) date. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. If date1 is earlier than date2 , then the result is negative. 1) date. DATE_ADD () Add time values (intervals) to a date value. Also, since you mentioned SAS, here is the SAS syntax to do the same thing: WHERE d_date > intnx ('MONTH', today (), -6, 'SAME');Query Manager inserts the expression into the SQL for you. 10 Answers. DECLARE @date datetime2 = '2021-01-07 14:36:17. Once you have the date difference, you can use simple techniques to express the difference in days, hours, minutes or seconds. We will use the below date for the examples. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. SYSTIMESTAMP). DATE_DIFF. subtracting date literals as pure dates without conversion. The key is to use DATEADD and DATEDIFF along with the appropriate SQL timespan enumeration. The easiest is the connect by level method: Copy code snippet. The values to compare. startdate, DATEDIFF(DAY,e1. 2 -Increment by 1 into total months count -. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. DatePart. Add a comment. S is milliseconds in one or up. The following shows the syntax of the syntax of the NEXT_DAY() function:. If you want an integer number of days. Syntax:DATEDIFF Examples Using All Options. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. - Find the “date_diff” in hours and multiply it by “60”. Month and day of the year don’t appear to be factored into the equation. Which leads me to believe that it is treating February. Below is a syntax for the DATEDIFF () function. DATEENTERED ,* from sometable S where S. The month and the last day of the month are defined by the parameter. The following query selects all rows with a date_col value from within the last 30 days: . 997 All results I use in BETWEEN operator, therefore last 'day' should include last millisecond of the very day. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. select datediff (q,'03-30-2005','04-01-2005') will return 1. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). substr (to_char (to_date ('01-02-2018','mm-dd-yyyy'), <NLS_DATE_FORMAT>),4,3) The usual default value (for English-language versions of. We would like to show you a description here but the site won’t allow us. Tdy. select level rn from dual connect by level <= 3; RN 1 2 3. Last 3 Months. This means that multiple references to a function. This is so as for the ease of use later for php. Date ) AS NextDate FROM. from a date time value. The format argument is optional. Also, you can check this for minutes : Oracle : how to subtract two dates and get minutes of the result. So given Netezza is based on PostgreSQL, so it's AGE function, is equivalent to Snowflake's DATEDIFF, but like PostgreSQL interval it defaults to expressing it in simplified terms of Years/Months/Days. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. SQL DATEPART. Converting a raw number of days into a number of weeks and days is pretty simple. 14. DATEDIFF(month, 0, GETDATE()) will give you the number of months from 1900-01-01 until now. mm is a two digits of minute (00 through 59). 9. Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. So you just have to multiply to get the result in minutes instead: SELECT (date2 - date1) * 24 * 60 AS minutesBetween FROM. Join our newsletter and get access to exclusive content every month. This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. 15 between 2 values that are 1 year, 1 month and 15 days apart. DATE_ADD. For example, this function returns 1. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. Also, according to Oracle's documentation LAST_DAY returns a DATE. If you want an integer. . Syntax %DateAdd(date_from, add_days) Description. The two date fields are "timestamp" format (date and time). Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 DateDiff is not a function that exists in Oracle. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. Date > T1. 天：. The application passes in two parameters: a string representing the number of the desired month (i. datediff isn't a function in Oracle. ;-). DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. But your query is giving the last date of previous month. The value can be a string literal or can be unquoted (e. I see that marked final solution is not correct always. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. Concatenates a date to a time on either side of the + symbol and returns a TIMESTAMP or TIMESTAMPTZ. You may have to re-cast to a DATE datatype first. Oracle doesn't have a DATEDIFF() function. If you are comparing to a date column in a existing table, then you need the date part too as you want to know December of which year was the previous month. Join our newsletter and get access to exclusive content every month. date_from, evnt. COMPUTE days3 = CTIME. The name of the order date month is printed, followed by the day of the month, a comma, and four-digit year. Oracle DATEDIFF函数在Oracle中的使用 在本文中，我们将介绍Oracle数据库中的DATEDIFF函数。 阅读更多：Oracle 教程 什么是DATEDIFF函数？ DATEDIFF函数用于计算两个日期之间的时间间隔。它可以在Oracle数据库中使用，并返回一个整数值，表示两个日期之间的差异。这对于计算两个日期之间的天数、小时数、分钟. This command prints the order date in the specified format. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters): select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual; 26,4729751904122. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. NEW_TIME returns the date and time in time zone timezone2 when date and time in time zone timezone1 are date. g. ). select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. subtract and give the difference in number of months. Next to calculate a month of services in a company by a user we would use ‘m’ to calculate the difference value. DATEADD (date part, units, date or datetime) Return date math results: datetime DATEDIFF (date part, start date, end date) Give the difference between 2 dates in units specified by. two full prior months plus the current partial month. 4k 4 4 gold badges 40 40 silver badges 53 53 bronze badges. MONTHS_BETWEEN returns number of months between dates date1 and date2. Add 18 years to the date in the BirthDate column, then return the date: SELECT LastName, BirthDate, DATEADD (year, 18, BirthDate) AS DateAdd FROM Employees; Try it Yourself ». I guess I did not read the question in depth. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. Learn more about Teams dp_monthは、入力日付を取得する月間の距離を返します。 (2006年10月) - 2005年6月= 16) dp_weekは、入力日付を取得する週間の距離を返します。 各標準カレンダ週は日曜日に始まり、7日にまたがるように定義されています。 (2006年10月10日 - 2005年6月14日= 69) Converting a raw number of days into a number of weeks and days is pretty simple. In my opinion the date diff is kind of subjective, especially on days. DateDiff ( date1, date2, date_part) パラメータ 説明; date1. Third, the more verbose method. to get the date one second before midnight of. 2258064516 DATE_DIFF = 1. 65. DateDiff function and I think it may have a parameter for indicating "in months" . Modified 1 year, 3 months ago. Share. To calculate the number of days between date1 and date2, you can use either Day of. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. Example. Based on Andriy's eagle-eyes, here is (I think) the DB2 syntax: WHERE d_date > current_date - 6 MONTHS. (You can also subtract fractions of days, but that might be outside the scope of this answer. ReturnDate) AS nvarchar(max)) END) AS [Duration] As a side note: I used nvarchar(max) for consistency with the first part of your query. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. 1. Oracle Month to Date:Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. 0 months apart:Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. Second option is wrong when start hours/minutes/seconds is less then end. This is from my own library, will return the difference of months between two dates. ADD_MONTHS returns slightly different results than DATEADD used with a MONTH component:. 3. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. Basic WHERE (Actual,. Possible values: text representing an entry in the IANA time zone database. Syntax. Assuming that a. It helps me a lot . date_open are both of type date, you can simply subtract them to get a difference in days. Was this tutorial helpful? Previously Oracle ROW_NUMBER Up Next Oracle ADD_MONTHS This tutorial provides you with the most commonly used Oracle date. two-digit days. 0. sql. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. 2) format. We’re calculating months of service in this example. I have to get the date from the system and calculate the date difference in days. (year/month/date from date) //oracle function for extracting values from date. Sorted by: 55. Field or Control. Here's how it does this: First the DATE function creates the date, 5/1/2016. If the year diff has to be counted this way then use: EXTRACT (YEAR FROM date_to) - EXTRACT (YEAR FROM date_from) Just for the log. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Returns a date string or the current date. Functions are based on a date-time serial number that equals the number of days since December 30, 1899. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. date1. Example 2. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. 3. DATEDIFF Examples Using All Options. 2. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. You could always create your own custom function in the module: Function MonthDiff (startdate, enddate) ' return number of months between two dates. The first one involves getting the difference in days and then converting it to 'x year y month z days'. If this solve your problem, here's the sql server syntax, just replace the variable @yourDate with your column name. The format argument is a string format that specifies which unit the date should be rounded to. mm is a two digits of minute (00 through 59). It works according to the Gregorian Calendar. Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. enddate,e3. The SQL code is "where fac. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. g. adddate addtime curdate current_date current_time current_timestamp curtime date datediff date_add date_format date_sub day dayname dayofmonth dayofweek dayofyear extract from_days hour last_day localtime localtimestamp makedate maketime. You want to pass TIMESTAMP arguments to the function and when you add years you also need to ensure that you propagate the fractional component of the timestamp (since ADD_MONTHS returns a DATE data-type without fractional seconds): SQL Server ignores that this is just one day. The second row is only 30 minutes apart, so the difference is 0. , NextDate, DATEDIFF("D", Date, NextDate) FROM ( SELECT ID, AccountNumber, Date, ( SELECT MIN(Date) FROM YourTable T2 WHERE T2. #. If i change the month in the first date to Feb (02) I get something strange. 2425): datediff (day, {start-date}, {end-date},) / 365. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. As GMB has mentioned in the comment above, date functions depend on the database type you are using. Sum (r => EF. v_weekenddays := floor (v_interval / 7) * 2; -- calculate aproximate number of weekend days between the two dates. Calculates the difference in week numbers and year numbers, subtracts the week numbers and then multiplies the result by 2 to calculate number of non-workdays between the two dates. . Select name,surname,datediff(YY,birthDate,getdate()) as age from students order by age. 2258064516. 25) This seems to be another common approach - and was also given in a comment on my question. 4193548 The number of whole months can be split into. Description. After executing the above query, we got the following output: SHOW_DAY. So it's not an accumulative difference, it's only when a date is within a smaller month. MONTH, YEAR, WEEK, etc are not allowed for. DATEDIFF(date1, date2) Parameter Values. Multiply the result of step 1 by 12 to transform it to months 3. mysql> SELECT. create table test_table ( customer_num NUMBER, card_number char(2), card_issue_date DATE, card_expire_date DATE ). DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. e. Share. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. * 12 + (Extract(Month From CDate(EndDate)) - Extract(Month. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. If date1 is earlier than date2, then the result is negative. Enter a date format string that describes the Date2 parameter. For example, PERIODROLLING can compute sales for a period that starts at a quarter before and ends at a quarter after the current quarter. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. 可以用以下方法在oracle中实现该函数的功能: 1. MONTHS_BETWEEN returns number of months between dates date1 and date2. To answer your question to find all records that occurred last month. select dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate() )+1, 0)) Last Day of Current YearRemarks. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. The system always returns a positive number regardless of. ArrivalDate, Trips. DATEDIFF(expr1,expr2) DATEDIFF() は、ある日付から別の日付までの日数の値として表現された expr1 − expr2 を返します。expr1 および expr2 は、日付または日付時間式です。 値の日付部分のみが計算に使用されます。One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. here i am trying get the month differences between two. Date. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. 032258 the problem lies in the fact that a month is a nebulous thing - it is not a precise number of days. Add a number of months (n) to a date and return the same day which is n of months away. Commonly used datepart units include month or second. The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN( DATE '2017-07-01', DATE '2017-01-01') MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: with cte (start_date, end_date) as ( select date '2020-10-01', date '2020-11-02' from dual ), rcte (start_date, end_date, part_month) as ( select start_date, end_date, trunc(start_date, 'MM') from cte union all select start_date, end_date, part_month + interval '1' month from rcte where part_month < trunc(end_date, 'MM') ) select extract(month. Hot. 'month' or month). Now I see two ways to achieve this: The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). It counts the number of year boundaries between two dates. SYSDATE is already a date. 取得一季中的第一天：. PeopleTools uses the SQL directly from the view definition (view text) and doesn't generate anything, so no meta-SQL wrapping is done. Here is the synopsis: If using Oracle use the trunc and numtoyminterval functions; if using SQL Server use the datediff function. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. Syntax:. Here is an example that uses date functions. 1 Answer. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. DATEDIFF() Returns the difference between the two dates. It is a function of SQL server. And then we need to convert the output of DATEPART to a 2-digit month number. The int data type takes 4 bytes as storage size whereas. Just divide the total by 7 to get the weeks and then calculate the remaining days. ) and rest are two dates which you want to compare. The following query returns weekly sales for the last 6 months for the product Cola in the market California. The syntax for these extended functions is. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between.